G-Force
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I need physics help please =)?
1) A 1200-kg car rounds a curve of radius 67 m banked at an angle of 12 degrees. If the car is traveling at 95 km/h, will a friction force be required? If so, how much?
2) A jet plane flying at 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of the loop in which the plane is flying? (Do you use 4mg-mg = mv^2/r)
3) What minimum banking angle is required for an Olympic bobsled to negotiate a 100-m radius turn at 35 m/s without skidding? (Ignore friction) (Do you use tan(theta) = v^2/rg)
4) The banking angle in a turn on the olympic bobsled track is not constant, but increases upward from the horizontal. Coming around turn, the bobsled team will intentionally "climb the wall," then go lower coming out of the turn. why do they do this?
(a) to take the turn at a faster speed <— I think this is the answer
(b) to give the team better control, because they are able to see ahead of them
(c) to prevent the bobsled from turning over
(d) to reduce the g-force on them
5) A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still negotiate the curve if the horizontal component of the normal force on the car from the road is equal in magnitude to
(a) mg/2
(b) tan[v^2/(rg)]
(c) mv^2/r <— I think this is the answer
(d) mg
Any help would be apappreciated! thanks =)
1 A 1200 kg car rounds a curve of radius 67m banked at an angle of 12 degrees. If the car is traveling at 95 km/h, will a friction force be required? If so, how much and in what direction?
N = 1200 x cos 12*x 9.81 = 11514.78 N
N sin 12 = 11514.78 x 0.21 = 2418.1 N
m x v^2 / r = 1200 x ( 95 x1000 / 3600)^2 / 67 = 124.72 N
Friction force required = (2418.1 - 124.72) sin 12 = 476.82 N upwards direction of the bank.
#2
A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of the loop in which the plane is flying?
A) 640 m
B) 1200 m
C) 7100 m
D) 9200 m <<<<<
#4 Yes, you are correct
| Dec 13, 2009
